Paper 1, Section II, 22H

Linear Analysis | Part II, 2021

Let HH be a separable Hilbert space and {ei}\left\{e_{i}\right\} be a Hilbertian (orthonormal) basis of HH. Given a sequence (xn)\left(x_{n}\right) of elements of HH and x∞∈Hx_{\infty} \in H, we say that xnx_{n} weakly converges to x∞x_{\infty}, denoted xn→x∞x_{n} \rightarrow x_{\infty}, if ∀h∈H,lim⁡n→∞⟨xn,h⟩=⟨x∞,h⟩\forall h \in H, \lim _{n \rightarrow \infty}\left\langle x_{n}, h\right\rangle=\left\langle x_{\infty}, h\right\rangle.

(a) Given a sequence (xn)\left(x_{n}\right) of elements of HH, prove that the following two statements are equivalent:

(i) ∃x∞∈H\exists x_{\infty} \in H such that xn→x∞x_{n} \rightarrow x_{\infty};

(ii) the sequence (xn)\left(x_{n}\right) is bounded in HH and ∀i⩾1\forall i \geqslant 1, the sequence (⟨xn,ei⟩)\left(\left\langle x_{n}, e_{i}\right\rangle\right) is convergent.

(b) Let (xn)\left(x_{n}\right) be a bounded sequence of elements of HH. Show that there exists x∞∈Hx_{\infty} \in H and a subsequence (xϕ(n))\left(x_{\phi(n)}\right) such that xϕ(n)→x∞x_{\phi(n)} \rightarrow x_{\infty} in HH.

(c) Let (xn)\left(x_{n}\right) be a sequence of elements of HH and x∞∈Hx_{\infty} \in H be such that xn→x∞x_{n} \rightarrow x_{\infty}. Show that the following three statements are equivalent:

(i) lim⁡n→∞∥xn−x∞∥=0\lim _{n \rightarrow \infty}\left\|x_{n}-x_{\infty}\right\|=0;

(ii) lim⁡n→∞∥xn∥=∥x∞∥\lim _{n \rightarrow \infty}\left\|x_{n}\right\|=\left\|x_{\infty}\right\|;

(iii) ∀ϵ>0,∃I(ϵ)\forall \epsilon>0, \exists I(\epsilon) such that ∀n⩾1,∑i⩾I(ϵ)∣⟨xn,ei⟩∣2<ϵ\forall n \geqslant 1, \sum_{i \geqslant I(\epsilon)}\left|\left\langle x_{n}, e_{i}\right\rangle\right|^{2}<\epsilon.

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