Mathematics Tripos Papers

  • Part IA
  • Part IB
  • Part II
  • FAQ

Paper 4 , Section I, I

Number Theory | Part II, 2016

Compute the continued fraction expansion of 14\sqrt{14}14​, and use it to find two solutions to x2−14y2=2x^{2}-14 y^{2}=2x2−14y2=2 where xxx and yyy are positive integers.

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