Paper 3, Section II, B

Mathematical Biology | Part II, 2016

The Fitzhugh-Nagumo model is given by

u˙=c(v+u13u3+z(t))v˙=1c(ua+bv)\begin{aligned} \dot{u} &=c\left(v+u-\frac{1}{3} u^{3}+z(t)\right) \\ \dot{v} &=-\frac{1}{c}(u-a+b v) \end{aligned}

where (123b)<a<1,0<b1\left(1-\frac{2}{3} b\right)<a<1,0<b \leqslant 1 and c1c \gg 1.

For z(t)=0z(t)=0, by considering the nullclines in the (u,v)(u, v)-plane, show that there is a unique equilibrium. Sketch the phase diagram

At t=0t=0 the system is at the equilibrium, and z(t)z(t) is then 'switched on' to be z(t)=V0z(t)=-V_{0} for t>0t>0, where V0V_{0} is a constant. Describe carefully how suitable choices of V0>0V_{0}>0 can represent a system analogous to (i) a neuron firing once, and (ii) a neuron firing repeatedly. Illustrate your answer with phase diagrams and also plots of vv against tt for each case. Find the threshold for V0V_{0} that separates these cases. Comment briefly from a biological perspective on the behaviour of the system when a=123b+ϵba=1-\frac{2}{3} b+\epsilon b and 0<ϵ10<\epsilon \ll 1.

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