Paper 4, Section II, B

General Relativity | Part II, 2010

The Schwarzschild line element is given by

ds2=Fdt2+F1dr2+r2(dθ2+sin2θdϕ2)d s^{2}=-F d t^{2}+F^{-1} d r^{2}+r^{2}\left(d \theta^{2}+\sin ^{2} \theta d \phi^{2}\right)

where F=1rs/rF=1-r_{s} / r and rsr_{s} is the Schwarzschild radius. Obtain the equation of geodesic motion of photons moving in the equatorial plane, θ=π/2\theta=\pi / 2, in the form

(drdτ)2=E2h2Fr2\left(\frac{d r}{d \tau}\right)^{2}=E^{2}-\frac{h^{2} F}{r^{2}}

where τ\tau is proper time, and EE and hh are constants whose physical significance should be indicated briefly.

Defining u=1/ru=1 / r show that light rays are determined by

(dudϕ)2=(1b)2u2+rsu3\left(\frac{d u}{d \phi}\right)^{2}=\left(\frac{1}{b}\right)^{2}-u^{2}+r_{s} u^{3}

where b=h/Eb=h / E and rsr_{s} may be taken to be small. Show that, to zeroth order in rsr_{s}, a light ray is a straight line passing at distance bb from the origin. Show that, to first order in rsr_{s}, the light ray is deflected through an angle 2rs/b2 r_{s} / b. Comment briefly on some observational evidence for the result.

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