1.I.6B

Mathematical Biology | Part II, 2007

A chemostat is a well-mixed tank of given volume V0V_{0} that contains water in which lives a population N(t)N(t) of bacteria that consume nutrient whose concentration is C(t)C(t) per unit volume. An inflow pipe supplies a solution of nutrient at concentration C0C_{0} and at a constant flow rate of QQ units of volume per unit time. The mixture flows out at the same rate through an outflow pipe. The bacteria consume the nutrient at a rate NK(C)N K(C), where

K(C)=KmaxCK0+CK(C)=\frac{K_{\max } C}{K_{0}+C}

and the bacterial population grows at a rate γNK(C)\gamma N K(C), where 0<γ<10<\gamma<1.

Write down the differential equations for N(t),C(t)N(t), C(t) and show that they can be rescaled into the following form:

dndτ=αcn1+cndcdτ=cn1+cc+β\begin{aligned} &\frac{d n}{d \tau}=\alpha \frac{c n}{1+c}-n \\ &\frac{d c}{d \tau}=-\frac{c n}{1+c}-c+\beta \end{aligned}

where α,β\alpha, \beta are positive constants, to be found.

Show that this system of equations has a non-trivial steady state if α>1\alpha>1 and β>1α1\beta>\frac{1}{\alpha-1}, and that it is stable.

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