4.II.37B

Fluid Dynamics II | Part II, 2006

A line force of magnitude FF is applied in the positive xx-direction to an unbounded fluid, generating a thin two-dimensional jet along the positive xx-axis. The fluid is at rest at y=±y=\pm \infty and there is negligible motion in x<0x<0. Write down the pressure gradient within the boundary layer. Deduce that the function M(x)M(x) defined by

M(x)=ρu2(x,y)dyM(x)=\int_{-\infty}^{\infty} \rho u^{2}(x, y) d y

is independent of xx for x>0x>0. Interpret this result, and explain why M=FM=F. Use scaling arguments to deduce that there is a similarity solution having stream function

ψ=(Fνx/ρ)1/3f(η) where η=y(F/ρν2x2)1/3\psi=(F \nu x / \rho)^{1 / 3} f(\eta) \quad \text { where } \quad \eta=y\left(F / \rho \nu^{2} x^{2}\right)^{1 / 3}

Hence show that ff satisfies

3f+f2+ff=0.3 f^{\prime \prime \prime}+f^{\prime 2}+f f^{\prime \prime}=0 .

Show that a solution of ()(*) is

f(η)=Atanh(Aη/6)f(\eta)=A \tanh (A \eta / 6)

where AA is a constant to be determined by requiring that MM is independent of xx. Find the volume flux, Q(x)Q(x), in the jet. Briefly indicate why Q(x)Q(x) increases as xx increases.

[Hint: You may use sech4(x)dx=4/3.]\left.\int_{-\infty}^{\infty} \operatorname{sech}^{4}(x) d x=4 / 3 .\right]

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