A1.18

Transport Processes | Part II, 2001

(i) The diffusion equation for a spherically-symmetric concentration field C(r,t)C(r, t) is

Ct=Dr2(r2Cr)r,C_{t}=\frac{D}{r^{2}}\left(r^{2} C_{r}\right)_{r},

where rr is the radial coordinate. Find and sketch the similarity solution to (1) which satisfies C0C \rightarrow 0 as rr \rightarrow \infty and 04πr2C(r,t)dr=M=\int_{0}^{\infty} 4 \pi r^{2} C(r, t) d r=M= constant, assuming it to be of the form

C=M(Dt)aF(η),η=r(Dt)b,C=\frac{M}{(D t)^{a}} F(\eta), \quad \eta=\frac{r}{(D t)^{b}},

where aa and bb are numbers to be found.

(ii) A two-dimensional piece of heat-conducting material occupies the region ara \leqslant r \leqslant b,π/2θπ/2b,-\pi / 2 \leqslant \theta \leqslant \pi / 2 (in plane polar coordinates). The surfaces r=a,θ=π/2,θ=π/2r=a, \theta=-\pi / 2, \theta=\pi / 2 are maintained at a constant temperature T1T_{1}; at the surface r=br=b the boundary condition on temperature T(r,θ)T(r, \theta) is

Tr+βT=0,T_{r}+\beta T=0,

where β>0\beta>0 is a constant. Show that the temperature, which satisfies the steady heat conduction equation

Trr+1rTr+1r2Tθθ=0,T_{r r}+\frac{1}{r} T_{r}+\frac{1}{r^{2}} T_{\theta \theta}=0,

is given by a Fourier series of the form

TT1=K+n=0cos(αnθ)[An(ra)2n+1+Bn(ar)2n+1]\frac{T}{T_{1}}=K+\sum_{n=0}^{\infty} \cos \left(\alpha_{n} \theta\right)\left[A_{n}\left(\frac{r}{a}\right)^{2 n+1}+B_{n}\left(\frac{a}{r}\right)^{2 n+1}\right]

where K,αn,An,BnK, \alpha_{n}, A_{n}, B_{n} are to be found.

In the limits a/b1a / b \ll 1 and βb1\beta b \ll 1, show that

π/2π/2TrrdθπβbT1\int_{-\pi / 2}^{\pi / 2} T_{r} r d \theta \approx-\pi \beta b T_{1}

given that

n=01(2n+1)2=π28.\sum_{n=0}^{\infty} \frac{1}{(2 n+1)^{2}}=\frac{\pi^{2}}{8} .

Explain how, in these limits, you could have obtained this result much more simply.

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