Show that $\|f\|_{1}=\int_{0}^{1}|f(x)| d x$ defines a norm on the space $C([0,1])$ of continuous functions $f:[0,1] \rightarrow \mathbb{R}$.

Let $\mathcal{S}$ be the set of continuous functions $g:[0,1] \rightarrow \mathbb{R}$ with $g(0)=g(1)=0$. Show that for each continuous function $f:[0,1] \rightarrow \mathbb{R}$, there is a sequence $g_{n} \in \mathcal{S}$ with $\sup _{x \in[0,1]}\left|g_{n}(x)\right| \leqslant \sup _{x \in[0,1]}|f(x)|$ such that $\left\|f-g_{n}\right\|_{1} \rightarrow 0$ as $n \rightarrow \infty$

Show that if $f:[0,1] \rightarrow \mathbb{R}$ is continuous and $\int_{0}^{1} f(x) g(x) d x=0$ for every $g \in \mathcal{S}$ then $f=0$.