Paper 4, Section II, G

Analysis II | Part IB, 2015

Consider the space \ell^{\infty} of bounded real sequences x=(xi)i=1x=\left(x_{i}\right)_{i=1}^{\infty} with the norm x=supixi\|x\|_{\infty}=\sup _{i}\left|x_{i}\right|. Show that for every bounded sequence x(n)x^{(n)} in \ell^{\infty} there is a subsequence x(nj)x^{\left(n_{j}\right)} which converges in every coordinate, i.e. the sequence (xi(nj))j=1\left(x_{i}^{\left(n_{j}\right)}\right)_{j=1}^{\infty} of real numbers converges for each ii. Does every bounded sequence in \ell^{\infty} have a convergent subsequence? Justify your answer.

Let 1\ell^{1} \subset \ell^{\infty} be the subspace of real sequences x=(xi)i=1x=\left(x_{i}\right)_{i=1}^{\infty} such that i=1xi\sum_{i=1}^{\infty}\left|x_{i}\right| converges. Is 1\ell^{1} complete in the norm \|\cdot\|_{\infty} (restricted from \ell^{\infty} to 1)\left.\ell^{1}\right) ? Justify your answer.

Suppose that (xi)\left(x_{i}\right) is a real sequence such that, for every (yi)\left(y_{i}\right) \in \ell^{\infty}, the series i=1xiyi\sum_{i=1}^{\infty} x_{i} y_{i} converges. Show that (xi)1.\left(x_{i}\right) \in \ell^{1} .

Suppose now that (xi)\left(x_{i}\right) is a real sequence such that, for every (yi)1\left(y_{i}\right) \in \ell^{1}, the series i=1xiyi\sum_{i=1}^{\infty} x_{i} y_{i} converges. Show that (xi).\left(x_{i}\right) \in \ell^{\infty} .

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