Paper 4, Section II, G

Analysis II | Part IB, 2015

Consider the space ℓ∞\ell^{\infty} of bounded real sequences x=(xi)i=1∞x=\left(x_{i}\right)_{i=1}^{\infty} with the norm ∥x∥∞=sup⁡i∣xi∣\|x\|_{\infty}=\sup _{i}\left|x_{i}\right|. Show that for every bounded sequence x(n)x^{(n)} in ℓ∞\ell^{\infty} there is a subsequence x(nj)x^{\left(n_{j}\right)} which converges in every coordinate, i.e. the sequence (xi(nj))j=1∞\left(x_{i}^{\left(n_{j}\right)}\right)_{j=1}^{\infty} of real numbers converges for each ii. Does every bounded sequence in ℓ∞\ell^{\infty} have a convergent subsequence? Justify your answer.

Let ℓ1⊂ℓ∞\ell^{1} \subset \ell^{\infty} be the subspace of real sequences x=(xi)i=1∞x=\left(x_{i}\right)_{i=1}^{\infty} such that ∑i=1∞∣xi∣\sum_{i=1}^{\infty}\left|x_{i}\right| converges. Is ℓ1\ell^{1} complete in the norm ∥⋅∥∞\|\cdot\|_{\infty} (restricted from ℓ∞\ell^{\infty} to ℓ1)\left.\ell^{1}\right) ? Justify your answer.

Suppose that (xi)\left(x_{i}\right) is a real sequence such that, for every (yi)∈ℓ∞\left(y_{i}\right) \in \ell^{\infty}, the series ∑i=1∞xiyi\sum_{i=1}^{\infty} x_{i} y_{i} converges. Show that (xi)∈ℓ1.\left(x_{i}\right) \in \ell^{1} .

Suppose now that (xi)\left(x_{i}\right) is a real sequence such that, for every (yi)∈ℓ1\left(y_{i}\right) \in \ell^{1}, the series ∑i=1∞xiyi\sum_{i=1}^{\infty} x_{i} y_{i} converges. Show that (xi)∈ℓ∞.\left(x_{i}\right) \in \ell^{\infty} .

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