Paper 2, Section I, E

Analysis II | Part IB, 2012

Let f:R2Rf: \mathbb{R}^{2} \rightarrow \mathbb{R} be a function. What does it mean to say that ff is differentiable at a point (x,y)R2?(x, y) \in \mathbb{R}^{2} ? Prove directly from this definition, that if ff is differentiable at (x,y)(x, y), then ff is continuous at (x,y)(x, y).

Let f:R2Rf: \mathbb{R}^{2} \rightarrow \mathbb{R} be the function:

f(x,y)={x2+y2 if x and y are rational 0 otherwise. f(x, y)= \begin{cases}x^{2}+y^{2} & \text { if } x \text { and } y \text { are rational } \\ 0 & \text { otherwise. }\end{cases}

For which points (x,y)R2(x, y) \in \mathbb{R}^{2} is ff differentiable? Justify your answer.

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