Paper 4, Section II, A

Complex Methods | Part IB, 2012

State the convolution theorem for Fourier transforms.

The function ϕ(x,y)\phi(x, y) satisfies

∇2ϕ=0\nabla^{2} \phi=0

on the half-plane y⩾0y \geqslant 0, subject to the boundary conditions

ϕ→0 as y→∞ for all xϕ(x,0)={1,∣x∣⩽10,∣x∣>1\begin{gathered} \phi \rightarrow 0 \text { as } y \rightarrow \infty \text { for all } x \\ \phi(x, 0)= \begin{cases}1, & |x| \leqslant 1 \\ 0, & |x|>1\end{cases} \end{gathered}

Using Fourier transforms, show that

ϕ(x,y)=yπ∫−111y2+(x−t)2 dt\phi(x, y)=\frac{y}{\pi} \int_{-1}^{1} \frac{1}{y^{2}+(x-t)^{2}} \mathrm{~d} t

and hence that

ϕ(x,y)=1π[tan⁡−1(1−xy)+tan⁡−1(1+xy)]\phi(x, y)=\frac{1}{\pi}\left[\tan ^{-1}\left(\frac{1-x}{y}\right)+\tan ^{-1}\left(\frac{1+x}{y}\right)\right]

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