A function f(z) has an isolated singularity at a, with Laurent expansion
f(z)=n=−∞∑∞cn(z−a)n
(a) Define res (f,a), the residue of f at the point a.
(b) Prove that if a is a pole of order k+1, then
res(f,a)=z→alimk!h(k)(z), where h(z)=(z−a)k+1f(z).
(c) Using the residue theorem and the formula above show that
∫−∞∞(1+x2)k+1dx=π(k!)2(2k)!4−k,k≥1