Paper 1, Section I, E

Mathematical Biology | Part II, 2015

The population density n(a,t)n(a, t) of individuals of age aa at time tt satisfies

nt+na=μ(a)n(a,t),n(0,t)=0b(a)n(a,t)da\frac{\partial n}{\partial t}+\frac{\partial n}{\partial a}=-\mu(a) n(a, t), \quad n(0, t)=\int_{0}^{\infty} b(a) n(a, t) d a

where μ(a)\mu(a) is the age-dependent death rate and b(a)b(a) is the birth rate per individual of age aa. Show that this may be solved with a similarity solution of the form n(a,t)=eγtr(a)n(a, t)=e^{\gamma t} r(a) if the growth rate γ\gamma satisfies ϕ(γ)=1\phi(\gamma)=1 where

ϕ(γ)=0b(a)eγa0aμ(s)dsda\phi(\gamma)=\int_{0}^{\infty} b(a) e^{-\gamma a-\int_{0}^{a} \mu(s) d s} d a

Suppose now that the birth rate is given by b(a)=Bapeλab(a)=B a^{p} e^{-\lambda a} with B,λ>0B, \lambda>0 and pp is a positive integer, and the death rate is constant in age (i.e. μ(a)=μ)\mu(a)=\mu). Find the average number of offspring per individual.

Find the similarity solution, and find the threshold BB^{*} for the birth parameter BB so that B>BB>B^{*} corresponds to a growing population.

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