1.II.15C

Classical Dynamics | Part II, 2005

(i) The action for a system with generalized coordinates (qa)\left(q_{a}\right) is given by

S=t1t2L(qa,q˙b)dtS=\int_{t_{1}}^{t_{2}} L\left(q_{a}, \dot{q}_{b}\right) d t

Derive Lagrange's equations from the principle of least action by considering all paths with fixed endpoints, δqa(t1)=δqa(t2)=0\delta q_{a}\left(t_{1}\right)=\delta q_{a}\left(t_{2}\right)=0.

(ii) A pendulum consists of a point mass mm at the end of a light rod of length ll. The pivot of the pendulum is attached to a mass MM which is free to slide without friction along a horizontal rail. Choose as generalized coordinates the position xx of the pivot and the angle θ\theta that the pendulum makes with the vertical.

Write down the Lagrangian and derive the equations of motion.

Find the frequency of small oscillations around the stable equilibrium.

Now suppose that a force acts on the pivot causing it to travel with constant acceleration in the xx-direction. Find the equilibrium angle θ\theta of the pendulum.

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