Paper 2, Section II, E

Analysis and Topology | Part IB, 2020

Let C[0,1]C[0,1] be the space of continuous real-valued functions on [0,1][0,1], and let d1,d∞d_{1}, d_{\infty} be the metrics on it given by

d1(f,g)=∫01∣f(x)−g(x)∣dx and d∞(f,g)=max⁡x∈[0,1]∣f(x)−g(x)∣d_{1}(f, g)=\int_{0}^{1}|f(x)-g(x)| d x \quad \text { and } \quad d_{\infty}(f, g)=\max _{x \in[0,1]}|f(x)-g(x)|

Show that id : (C[0,1],d∞)→(C[0,1],d1)\left(C[0,1], d_{\infty}\right) \rightarrow\left(C[0,1], d_{1}\right) is a continuous map. Do d1d_{1} and d∞d_{\infty} induce the same topology on C[0,1]C[0,1] ? Justify your answer.

Let dd denote for any m∈Nm \in \mathbb{N} the uniform metric on Rm:d((xi),(yi))=max⁡i∣xi−yi∣\mathbb{R}^{m}: d\left(\left(x_{i}\right),\left(y_{i}\right)\right)=\max _{i}\left|x_{i}-y_{i}\right|. Let Pn⊂C[0,1]\mathcal{P}_{n} \subset C[0,1] be the subspace of real polynomials of degree at most nn. Define a Lipschitz map between two metric spaces, and show that evaluation at a point gives a Lipschitz map (C[0,1],d∞)→(R,d)\left(C[0,1], d_{\infty}\right) \rightarrow(\mathbb{R}, d). Hence or otherwise find a bijection from (Pn,d∞)\left(\mathcal{P}_{n}, d_{\infty}\right) to (Rn+1,d)\left(\mathbb{R}^{n+1}, d\right) which is Lipschitz and has a Lipschitz inverse.

Let P~n⊂Pn\tilde{\mathcal{P}}_{n} \subset \mathcal{P}_{n} be the subset of polynomials with values in the range [−1,1][-1,1].

(i) Show that (P~n,d∞)\left(\tilde{\mathcal{P}}_{n}, d_{\infty}\right) is compact.

(ii) Show that d1d_{1} and d∞d_{\infty} induce the same topology on P~n\tilde{\mathcal{P}}_{n}.

Any theorems that you use should be clearly stated.

[You may use the fact that for distinct constants aia_{i}, the following matrix is invertible:

(1a0a02…a0n1a1a12…a1n⋮⋮⋮⋮1anan2…ann)\left(\begin{array}{ccccc} 1 & a_{0} & a_{0}^{2} & \ldots & a_{0}^{n} \\ 1 & a_{1} & a_{1}^{2} & \ldots & a_{1}^{n} \\ \vdots & \vdots & \vdots & & \vdots \\ 1 & a_{n} & a_{n}^{2} & \ldots & a_{n}^{n} \end{array}\right)

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