Paper 3, Section II, G

Analysis II | Part IB, 2016

Let XX be a metric space.

(a) What does it mean to say that a function f:XRf: X \rightarrow \mathbb{R} is uniformly continuous? What does it mean to say that ff is Lipschitz? Show that if ff is Lipschitz then it is uniformly continuous. Show also that if (xn)n\left(x_{n}\right)_{n} is a Cauchy sequence in XX, and ff is uniformly continuous, then the sequence (f(xn))n\left(f\left(x_{n}\right)\right)_{n} is convergent.

(b) Let f:XRf: X \rightarrow \mathbb{R} be continuous, and XX be sequentially compact. Show that ff is uniformly continuous. Is ff necessarily Lipschitz? Justify your answer.

(c) Let YY be a dense subset of XX, and let g:YRg: Y \rightarrow \mathbb{R} be a continuous function. Show that there exists at most one continuous function f:XRf: X \rightarrow \mathbb{R} such that for all yYy \in Y, f(y)=g(y)f(y)=g(y). Prove that if gg is uniformly continuous, then such a function ff exists, and is uniformly continuous.

[A subset YXY \subset X is dense if for any nonempty open subset UXU \subset X, the intersection UYU \cap Y is nonempty.]

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