Paper 4, Section II, F

Linear Algebra | Part IB, 2016

(a) Let α:V→W\alpha: V \rightarrow W be a linear transformation between finite dimensional vector spaces over a field F=RF=\mathbb{R} or C\mathbb{C}.

Define the dual map of α\alpha. Let δ\delta be the dual map of α\alpha. Given a subspace U⊆VU \subseteq V, define the annihilator U∘U^{\circ} of UU. Show that (ker⁡α)∘(\operatorname{ker} \alpha)^{\circ} and the image of δ\delta coincide. Conclude that the dimension of the image of α\alpha is equal to the dimension of the image of δ\delta. Show that dim⁡ker⁡(α)−dim⁡ker⁡(δ)=dim⁡V−dim⁡W\operatorname{dim} \operatorname{ker}(\alpha)-\operatorname{dim} \operatorname{ker}(\delta)=\operatorname{dim} V-\operatorname{dim} W.

(b) Now suppose in addition that V,WV, W are inner product spaces. Define the adjoint α∗\alpha^{*} of α\alpha. Let β:U→V,γ:V→W\beta: U \rightarrow V, \gamma: V \rightarrow W be linear transformations between finite dimensional inner product spaces. Suppose that the image of β\beta is equal to the kernel of γ\gamma. Then show that ββ∗+γ∗γ\beta \beta^{*}+\gamma^{*} \gamma is an isomorphism.

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