Paper 4, Section II, C

Variational Principles | Part IB, 2014

Consider the integral

I=∫f(y,y′)dxI=\int f\left(y, y^{\prime}\right) d x

Show that if ff satisfies the Euler-Lagrange equation, then

f−y′∂f∂y′= constant. f-y^{\prime} \frac{\partial f}{\partial y^{\prime}}=\text { constant. }

An axisymmetric soap film y(x)y(x) is formed between two circular wires at x=±lx=\pm l. The wires both have radius rr. Show that the shape that minimises the surface area takes the form

y(x)=kcosh⁡xky(x)=k \cosh \frac{x}{k}

Show that there exist two possible kk that satisfy the boundary conditions for r/lr / l sufficiently large.

Show that for these solutions the second variation is given by

δ2I=π∫−l+l(kη′2−1kη2)sech⁡2(xk)dx\delta^{2} I=\pi \int_{-l}^{+l}\left(k \eta^{\prime 2}-\frac{1}{k} \eta^{2}\right) \operatorname{sech}^{2}\left(\frac{x}{k}\right) d x

where η\eta is an axisymmetric perturbation with η(±l)=0\eta(\pm l)=0.

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