Paper 4, Section II, A

Fluid Dynamics | Part IB, 2013

The axisymmetric, irrotational flow generated by a solid sphere of radius aa translating at velocity UU in an inviscid, incompressible fluid is represented by a velocity potential ϕ(r,θ)\phi(r, \theta). Assume the fluid is at rest far away from the sphere. Explain briefly why 2ϕ=0\nabla^{2} \phi=0.

By trying a solution of the form ϕ(r,θ)=f(r)g(θ)\phi(r, \theta)=f(r) g(\theta), show that

ϕ=Ua3cosθ2r2\phi=-\frac{U a^{3} \cos \theta}{2 r^{2}}

and write down the fluid velocity.

Show that the total kinetic energy of the fluid is kMU2/4k M U^{2} / 4 where MM is the mass of the sphere and kk is the ratio of the density of the fluid to the density of the sphere.

A heavy sphere (i.e. k<1k<1 ) is released from rest in an inviscid fluid. Determine its speed after it has fallen a distance hh in terms of M,k,gM, k, g and hh.

Note, in spherical polars:

ϕ=ϕrer+1rϕθeθ2ϕ=1r2r(r2ϕr)+1r2sinθθ(sinθϕθ)\begin{gathered} \boldsymbol{\nabla} \phi=\frac{\partial \phi}{\partial r} \mathbf{e}_{\mathbf{r}}+\frac{1}{r} \frac{\partial \phi}{\partial \theta} \mathbf{e}_{\theta} \\ \nabla^{2} \phi=\frac{1}{r^{2}} \frac{\partial}{\partial r}\left(r^{2} \frac{\partial \phi}{\partial r}\right)+\frac{1}{r^{2} \sin \theta} \frac{\partial}{\partial \theta}\left(\sin \theta \frac{\partial \phi}{\partial \theta}\right) \end{gathered}

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