Paper 4, Section II, A

Complex Methods | Part IB, 2010

A linear system is described by the differential equation

y(t)y(t)2y(t)+2y(t)=f(t),y^{\prime \prime \prime}(t)-y^{\prime \prime}(t)-2 y^{\prime}(t)+2 y(t)=f(t),

with initial conditions

y(0)=0,y(0)=1,y(0)=1y(0)=0, \quad y^{\prime}(0)=1, \quad y^{\prime \prime}(0)=1

The Laplace transform of f(t)f(t) is defined as

L[f(t)]=f~(s)=0estf(t)dt\mathcal{L}[f(t)]=\tilde{f}(s)=\int_{0}^{\infty} e^{-s t} f(t) d t

You may assume the following Laplace transforms,

L[y(t)]=y~(s)L[y(t)]=sy~(s)y(0)L[y(t)]=s2y~(s)sy(0)y(0)L[y(t)]=s3y~(s)s2y(0)sy(0)y(0)\begin{aligned} \mathcal{L}[y(t)] &=\tilde{y}(s) \\ \mathcal{L}\left[y^{\prime}(t)\right] &=s \tilde{y}(s)-y(0) \\ \mathcal{L}\left[y^{\prime \prime}(t)\right] &=s^{2} \tilde{y}(s)-s y(0)-y^{\prime}(0) \\ \mathcal{L}\left[y^{\prime \prime \prime}(t)\right] &=s^{3} \tilde{y}(s)-s^{2} y(0)-s y^{\prime}(0)-y^{\prime \prime}(0) \end{aligned}

(a) Use Laplace transforms to determine the response, y1(t)y_{1}(t), of the system to the signal

f(t)=2f(t)=-2

(b) Determine the response, y2(t)y_{2}(t), given that its Laplace transform is

y~2(s)=1s2(s1)2.\tilde{y}_{2}(s)=\frac{1}{s^{2}(s-1)^{2}} .

(c) Given that

y(t)y(t)2y(t)+2y(t)=g(t)y^{\prime \prime \prime}(t)-y^{\prime \prime}(t)-2 y^{\prime}(t)+2 y(t)=g(t)

leads to the response with Laplace transform

y~(s)=1s2(s1)2,\tilde{y}(s)=\frac{1}{s^{2}(s-1)^{2}},

determine g(t)g(t).

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