Special Relativity | Part IB, 2003

What are the momentum and energy of a photon of wavelength λ\lambda ?

A photon of wavelength λ\lambda is incident on an electron. After the collision, the photon has wavelength λ\lambda^{\prime}. Show that

λλ=hmc(1cosθ),\lambda^{\prime}-\lambda=\frac{h}{m c}(1-\cos \theta),

where θ\theta is the scattering angle and mm is the electron rest mass.

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