2.I.2C

Methods | Part IB, 2003

Explain briefly why the second-rank tensor

SxixjdS(x)\int_{S} x_{i} x_{j} d S(\mathbf{x})

is isotropic, where SS is the surface of the unit sphere centred on the origin.

A second-rank tensor is defined by

Tij(y)=S(yixi)(yjxj)dS(x)T_{i j}(\mathbf{y})=\int_{S}\left(y_{i}-x_{i}\right)\left(y_{j}-x_{j}\right) d S(\mathbf{x})

where SS is the surface of the unit sphere centred on the origin. Calculate T(y)T(\mathbf{y}) in the form

Tij=λδij+μyiyjT_{i j}=\lambda \delta_{i j}+\mu y_{i} y_{j}

where λ\lambda and μ\mu are to be determined.

By considering the action of TT on y\mathbf{y} and on vectors perpendicular to y\mathbf{y}, determine the eigenvalues and associated eigenvectors of TT.

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