Let y1 and y2 be two linearly independent solutions to the differential equation
dx2d2y+p(x) dxdy+q(x)y=0.
Show that the Wronskian W=y1y2′−y2y1′ satisfies
dxdW+pW=0.
Deduce that if y2(x0)=0 then
y2(x)=y1(x)∫x0xy1(t)2W(t) dt.
Given that y1(x)=x3 satisfies the equation
x2 dx2d2y−x dxdy−3y=0
find the solution which satisfies y(1)=0 and y′(1)=1.