Mathematics Tripos Papers

  • Part IA
  • Part IB
  • Part II
  • FAQ

Paper 2, Section I, A

Differential Equations | Part IA, 2021

Solve the difference equation

yn+2−4yn+1+4yn=ny_{n+2}-4 y_{n+1}+4 y_{n}=nyn+2​−4yn+1​+4yn​=n

subject to the initial conditions y0=1y_{0}=1y0​=1 and y1=0y_{1}=0y1​=0.

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