Paper 1, Section I, ADifferential Equations | Part IA, 2020Solve the differential equationdydx=1x+e2y\frac{d y}{d x}=\frac{1}{x+e^{2 y}}dxdy=x+e2y1subject to the initial condition y(1)=0y(1)=0y(1)=0.Typos? Please submit corrections to this page on GitHub.