Paper 2, Section I, CDifferential Equations | Part IA, 2009Solve the differential equationd2y dx2−5dy dx+6y=e3x\frac{\mathrm{d}^{2} y}{\mathrm{~d} x^{2}}-5 \frac{\mathrm{d} y}{\mathrm{~d} x}+6 y=\mathrm{e}^{3 x} dx2d2y−5 dxdy+6y=e3xsubject to the conditions y=dy/dx=0y=\mathrm{d} y / \mathrm{d} x=0y=dy/dx=0 when x=0x=0x=0.Typos? Please submit corrections to this page on GitHub.