Mathematics Tripos Papers

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  • Part IB
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Paper 2, Section I, B

Differential Equations | Part IA, 2007

Find the solution y(x)y(x)y(x) of the equation

y′′−6y′+9y=cos⁡(2x)e3xy^{\prime \prime}-6 y^{\prime}+9 y=\cos (2 x) \mathrm{e}^{3 x}y′′−6y′+9y=cos(2x)e3x

that satisfies y(0)=0y(0)=0y(0)=0 and y′(0)=1y^{\prime}(0)=1y′(0)=1.

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